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24x^2+46x-4=0
a = 24; b = 46; c = -4;
Δ = b2-4ac
Δ = 462-4·24·(-4)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-50}{2*24}=\frac{-96}{48} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+50}{2*24}=\frac{4}{48} =1/12 $
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